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      • [Docker] Docker Commands
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      • [Jenkins] 1. Install Jenkins
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    • LeetCode Solutions
      • [LeetCode] 1. Two Sum [Easy]
      • [LeetCode] 2. Add Two Numbers [Medium]
      • [LeetCode] 3. Longest Substring Without Repeating Characters [Medium]
      • [LeetCode] 5. Longest Palindromic Substring [Medium]
      • [LeetCode] 7. Reverse Integer [Easy] [LeetCode]
      • [LeetCode] 8. String to Integer (atoi)
      • [LeetCode] 11. Container With Most Water
      • [LeetCode] 13. Roman to Integer
      • [LeetCode]14. Longest Common Prefix
      • [LeetCode] 15. 3Sum
      • [LeetCode] 17. Letter Combinations of a Phone Number
      • [LeetCode] 19. Remove Nth Node From End of List
      • [LeetCode] 20. Valid Parentheses
      • [LeetCode] 21. Merge Two Sorted Lists
      • [LeetCode] 22. Generate Parentheses
      • [LeetCode] 26. Remove Duplicates from Sorted Array
      • [LeetCode] 28. Implement strStr()
      • [LeetCode] 33. Search in Rotated Sorted Array
      • [LeetCode] 34. Find First and Last Position of Element in Sorted Array
      • [LeetCode]36. Valid Sudoku
      • [LeetCode] 38. Count and Say
      • [LeetCode] 46. Permutations
      • [LeetCode] 48. Rotate Image
      • [LeetCode] 49. Group Anagrams
  • Git
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      • [LeetCode] 50. Pow(x, n)
  • About Author
    • Frank Chen
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  1. Leet Code
  2. LeetCode Solutions

[LeetCode] 49. Group Anagrams

Given an array of strings, group anagrams together.

Example:

Input: ["eat", "tea", "tan", "ate", "nat", "bat"],
Output:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:

  • All inputs will be in lowercase.

  • The order of your output does not matter.

Analyse:

​

Solution:

class Solution {

    func groupAnagrams(_ strs: [String]) -> [[String]] {
        var copyStr = strs;
        var output:[[String]]  = [];
        var sortedStrs:[String:[String]] = [:];
        
        var i = 0;
        while(i < copyStr.count) {
            var str = copyStr[i];
            str = String(str.sorted{$0 < $1})
            
            if(sortedStrs[str] != nil) {
                var strs: [String] = sortedStrs[str]!;
                strs.append(copyStr[i]);
                sortedStrs[str] = strs;
            }
            else {
                sortedStrs[str] = [copyStr[i]]; 
            }
                
            i += 1;
        }

        for xxx in sortedStrs {
            output.append(xxx.value);
        }
        
        return output;
    } 
}
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Last updated 6 years ago